2*sin(2x)+cos(2x)=1

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Solution for 2*sin(2x)+cos(2x)=1 equation: 


Simplifying
2sin(2x) + cos(2x) = 1

Remove parenthesis around (2x)
2ins * 2x + cos(2x) = 1

Reorder the terms for easier multiplication:
2 * 2ins * x + cos(2x) = 1

Multiply 2 * 2
4ins * x + cos(2x) = 1

Multiply ins * x
4insx + cos(2x) = 1

Remove parenthesis around (2x)
4insx + cos * 2x = 1

Reorder the terms for easier multiplication:
4insx + 2cos * x = 1

Multiply cos * x
4insx + 2cosx = 1

Reorder the terms:
2cosx + 4insx = 1

Solving
2cosx + 4insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
2cosx + 4insx + -4insx = 1 + -4insx

Combine like terms: 4insx + -4insx = 0
2cosx + 0 = 1 + -4insx
2cosx = 1 + -4insx

Divide each side by '2osx'.
c = 0.5o-1s-1x-1 + -2ino-1

Simplifying
c = 0.5o-1s-1x-1 + -2ino-1

Reorder the terms:
c = -2ino-1 + 0.5o-1s-1x-1

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