2*sin(x)+3*cos(x)=2

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Solution for 2*sin(x)+3*cos(x)=2 equation: 


Simplifying
2sin(x) + 3cos(x) = 2

Multiply ins * x
2insx + 3cos(x) = 2

Multiply cos * x
2insx + 3cosx = 2

Reorder the terms:
3cosx + 2insx = 2

Solving
3cosx + 2insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2insx' to each side of the equation.
3cosx + 2insx + -2insx = 2 + -2insx

Combine like terms: 2insx + -2insx = 0
3cosx + 0 = 2 + -2insx
3cosx = 2 + -2insx

Divide each side by '3osx'.
c = 0.6666666667o-1s-1x-1 + -0.6666666667ino-1

Simplifying
c = 0.6666666667o-1s-1x-1 + -0.6666666667ino-1

Reorder the terms:
c = -0.6666666667ino-1 + 0.6666666667o-1s-1x-1

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