2+((3x-1)/x)=8

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Solution for 2+((3x-1)/x)=8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x-1)/x+2 = 8 // - 8

(3*x-1)/x-8+2 = 0

(3*x-1)/x+(-8*x)/x+(2*x)/x = 0

3*x-8*x+2*x-1 = 0

2*x-5*x-1 = 0

-3*x-1 = 0

(-3*x-1)/x = 0

(-3*x-1)/x = 0 // * x

-3*x-1 = 0

-3*x-1 = 0 // + 1

-3*x = 1 // : -3

x = 1/(-3)

x = -1/3

x = -1/3

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