2+(3w+2)/4=(2w+1)/2

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Solution for 2+(3w+2)/4=(2w+1)/2 equation: 


w in (-oo:+oo)

(3*w+2)/4+2 = (2*w+1)/2 // - (2*w+1)/2

(3*w+2)/4-((2*w+1)/2)+2 = 0

(3*w+2)/4+(-1*(2*w+1))/2+2 = 0

(2*(3*w+2))/(2*4)+(-1*4*(2*w+1))/(2*4)+(4*2^2)/(2*4) = 0

2*(3*w+2)-1*4*(2*w+1)+4*2^2 = 0

16-2*w = 0

(16-2*w)/(2*4) = 0

(16-2*w)/(2*4) = 0 // * 2*4

16-2*w = 0

16-2*w = 0 // - 16

-2*w = -16 // : -2

w = -16/(-2)

w = 8

w = 8

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