2+(3x+3)=12+(1x+3)

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Solution for 2+(3x+3)=12+(1x+3) equation: 



2+(3x+3)=12+(1x+3)

We move all terms to the left:

2+(3x+3)-(12+(1x+3))=0

We add all the numbers together, and all the variables

(3x+3)-(12+(x+3))+2=0

We get rid of parentheses

3x-(12+(x+3))+3+2=0



We calculate terms in parentheses: -(12+(x+3)), so:

12+(x+3)

determiningTheFunctionDomain
(x+3)+12

We get rid of parentheses

x+3+12

We add all the numbers together, and all the variables

x+15

Back to the equation:

-(x+15)



We add all the numbers together, and all the variables

3x-(x+15)+5=0

We get rid of parentheses

3x-x-15+5=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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