2+(3y-4)=2(y-3)

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Solution for 2+(3y-4)=2(y-3) equation:


Simplifying
2 + (3y + -4) = 2(y + -3)

Reorder the terms:
2 + (-4 + 3y) = 2(y + -3)

Remove parenthesis around (-4 + 3y)
2 + -4 + 3y = 2(y + -3)

Combine like terms: 2 + -4 = -2
-2 + 3y = 2(y + -3)

Reorder the terms:
-2 + 3y = 2(-3 + y)
-2 + 3y = (-3 * 2 + y * 2)
-2 + 3y = (-6 + 2y)

Solving
-2 + 3y = -6 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-2 + 3y + -2y = -6 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-2 + 1y = -6 + 2y + -2y

Combine like terms: 2y + -2y = 0
-2 + 1y = -6 + 0
-2 + 1y = -6

Add '2' to each side of the equation.
-2 + 2 + 1y = -6 + 2

Combine like terms: -2 + 2 = 0
0 + 1y = -6 + 2
1y = -6 + 2

Combine like terms: -6 + 2 = -4
1y = -4

Divide each side by '1'.
y = -4

Simplifying
y = -4

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