2+(8/1)-6a=2(4-a)+(4a/1)-18

Solution for 2+(8/1)-6a=2(4-a)+(4a/1)-18 equation:

2+(8/1)-6a=2(4-a)+(4a/1)-18

We move all terms to the left:

2+(8/1)-6a-(2(4-a)+(4a/1)-18)=0

We add all the numbers together, and all the variables

-6a-(2(-1a+4)+(+4a/1)-18)+2+0=0

We add all the numbers together, and all the variables

-6a-(2(-1a+4)+(+4a/1)-18)+2=0

We multiply all the terms by the denominator


-6a*1)-18)-(2(-1a+4a+4)+(+2*1)-18)=0

We add all the numbers together, and all the variables

-6a*1)-18)-(2(3a+4)+2-18)=0

We add all the numbers together, and all the variables

-6a*1)-18)-(2(3a=0

Wy multiply elements

-6a^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{-12}=0$