2+(b+2)=3(b-3)

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Solution for 2+(b+2)=3(b-3) equation:


Simplifying
2 + (b + 2) = 3(b + -3)

Reorder the terms:
2 + (2 + b) = 3(b + -3)

Remove parenthesis around (2 + b)
2 + 2 + b = 3(b + -3)

Combine like terms: 2 + 2 = 4
4 + b = 3(b + -3)

Reorder the terms:
4 + b = 3(-3 + b)
4 + b = (-3 * 3 + b * 3)
4 + b = (-9 + 3b)

Solving
4 + b = -9 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
4 + b + -3b = -9 + 3b + -3b

Combine like terms: b + -3b = -2b
4 + -2b = -9 + 3b + -3b

Combine like terms: 3b + -3b = 0
4 + -2b = -9 + 0
4 + -2b = -9

Add '-4' to each side of the equation.
4 + -4 + -2b = -9 + -4

Combine like terms: 4 + -4 = 0
0 + -2b = -9 + -4
-2b = -9 + -4

Combine like terms: -9 + -4 = -13
-2b = -13

Divide each side by '-2'.
b = 6.5

Simplifying
b = 6.5

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