2+(x*x)=(x-3)*(x-2)

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Solution for 2+(x*x)=(x-3)*(x-2) equation: 



2+(x*x)=(x-3)(x-2)

We move all terms to the left:

2+(x*x)-((x-3)(x-2))=0

We add all the numbers together, and all the variables

(+x*x)-((x-3)(x-2))+2=0

We get rid of parentheses

x*x-((x-3)(x-2))+2=0

We multiply parentheses ..

-((+x^2-2x-3x+6))+x*x+2=0



We calculate terms in parentheses: -((+x^2-2x-3x+6)), so:

(+x^2-2x-3x+6)

We get rid of parentheses

x^2-2x-3x+6

We add all the numbers together, and all the variables

x^2-5x+6

Back to the equation:

-(x^2-5x+6)



Wy multiply elements

x^2-(x^2-5x+6)+2=0

We get rid of parentheses

x^2-x^2+5x-6+2=0

We add all the numbers together, and all the variables

5x-4=0

We move all terms containing x to the left, all other terms to the right

5x=4

x=4/5

x=4/5

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