2+(x+5)(3x-4)=(3x+2)x-1+4x

Solution for 2+(x+5)(3x-4)=(3x+2)x-1+4x equation:

2+(x+5)(3x-4)=(3x+2)x-1+4x

We move all terms to the left:

2+(x+5)(3x-4)-((3x+2)x-1+4x)=0

We multiply parentheses ..

(+3x^2-4x+15x-20)-((3x+2)x-1+4x)+2=0


We calculate terms in parentheses: -((3x+2)x-1+4x), so:

(3x+2)x-1+4x

determiningTheFunctionDomain
(3x+2)x+4x-1

We add all the numbers together, and all the variables

4x+(3x+2)x-1

We multiply parentheses

3x^2+4x+2x-1

We add all the numbers together, and all the variables

3x^2+6x-1

Back to the equation:

-(3x^2+6x-1)


We get rid of parentheses

3x^2-3x^2-4x+15x-6x-20+1+2=0

We add all the numbers together, and all the variables

5x-17=0

We move all terms containing x to the left, all other terms to the right

5x=17

x=17/5

x=3+2/5