2+(x-5)=3-(x-4)

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Solution for 2+(x-5)=3-(x-4) equation: 



2+(x-5)=3-(x-4)

We move all terms to the left:

2+(x-5)-(3-(x-4))=0

We get rid of parentheses

x-(3-(x-4))-5+2=0



We calculate terms in parentheses: -(3-(x-4)), so:

3-(x-4)

determiningTheFunctionDomain
-(x-4)+3

We get rid of parentheses

-x+4+3

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We add all the numbers together, and all the variables

x-(-1x+7)-3=0

We get rid of parentheses

x+1x-7-3=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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