2+(y+2)=3y/4-3

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Solution for 2+(y+2)=3y/4-3 equation: 



2+(y+2)=3y/4-3

We move all terms to the left:

2+(y+2)-(3y/4-3)=0

We get rid of parentheses

y-3y/4+2+3+2=0

We multiply all the terms by the denominator


y*4-3y+2*4+3*4+2*4=0

We add all the numbers together, and all the variables

-3y+y*4+28=0

Wy multiply elements

-3y+4y+28=0

We add all the numbers together, and all the variables

y+28=0

We move all terms containing y to the left, all other terms to the right

y=-28

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