2+(y/2)=(3y/4)-3

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Solution for 2+(y/2)=(3y/4)-3 equation: 


y in (-oo:+oo)

y/2+2 = (3*y)/4-3 // - (3*y)/4-3

y/2-((3*y)/4)+2+3 = 0

y/2+(-3/4)*y+2+3 = 0

5-1/4*y = 0 // - 5

-1/4*y = -5 // : -1/4

y = -5/(-1/4)

y = 20

y = 20

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