2+1/3g=1+1/4g

Solution for 2+1/3g=1+1/4g equation:

2+1/3g=1+1/4g

We move all terms to the left:

2+1/3g-(1+1/4g)=0


Domain of the equation: 3g!=0

g!=0/3

g!=0

g∈R



Domain of the equation: 4g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

1/3g-(1/4g+1)+2=0

We get rid of parentheses

1/3g-1/4g-1+2=0

We calculate fractions


4g/12g^2+(-3g)/12g^2-1+2=0

We add all the numbers together, and all the variables

4g/12g^2+(-3g)/12g^2+1=0

We multiply all the terms by the denominator


4g+(-3g)+1*12g^2=0

Wy multiply elements

12g^2+4g+(-3g)=0

We get rid of parentheses

12g^2+4g-3g=0

We add all the numbers together, and all the variables

12g^2+g=0

a = 12; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*12}=\frac{-2}{24}
=-1/12
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*12}=\frac{0}{24}
=0
$