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2+1/b-2=3b/b+2
We move all terms to the left:
2+1/b-2-(3b/b+2)=0
Domain of the equation: b!=0
b∈R
Domain of the equation: b+2)!=0We add all the numbers together, and all the variables
b∈R
1/b-(3b/b+2)=0
We get rid of parentheses
1/b-3b/b-2=0
We multiply all the terms by the denominator
-3b-2*b+1=0
We add all the numbers together, and all the variables
-5b+1=0
We move all terms containing b to the left, all other terms to the right
-5b=-1
b=-1/-5
b=1/5
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