If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( u )
u = 0
u-2 = 0
u = 0
u = 0
u-2 = 0
u-2 = 0
u-2 = 0 // + 2
u = 2
u in (-oo:0) U (0:2) U (2:+oo)
1/u-7+2 = (5/(u-2))*(u-7) // - (5/(u-2))*(u-7)
1/u-((5/(u-2))*(u-7))-7+2 = 0
1/u-5*(u-7)*(u-2)^-1-7+2 = 0
(-5*(u-7))/(u-2)+1/u-7+2 = 0
(-5*u*(u-7))/(u*(u-2))+(1*(u-2))/(u*(u-2))+(-7*u*(u-2))/(u*(u-2))+(2*u*(u-2))/(u*(u-2)) = 0
1*(u-2)-5*u*(u-7)-7*u*(u-2)+2*u*(u-2) = 0
2*u^2-5*u^2-7*u^2+36*u+14*u-4*u-2 = 0
2*u^2-12*u^2+50*u-4*u-2 = 0
46*u-10*u^2-2 = 0
46*u-10*u^2-2 = 0
2*(23*u-5*u^2-1) = 0
23*u-5*u^2-1 = 0
DELTA = 23^2-(-5*(-1)*4)
DELTA = 509
DELTA > 0
u = (509^(1/2)-23)/(-5*2) or u = (-509^(1/2)-23)/(-5*2)
u = (509^(1/2)-23)/(-10) or u = (509^(1/2)+23)/10
2*(u-((509^(1/2)-23)/(-10)))*(u-((509^(1/2)+23)/10)) = 0
(2*(u-((509^(1/2)-23)/(-10)))*(u-((509^(1/2)+23)/10)))/(u*(u-2)) = 0
(2*(u-((509^(1/2)-23)/(-10)))*(u-((509^(1/2)+23)/10)))/(u*(u-2)) = 0 // * u*(u-2)
2*(u-((509^(1/2)-23)/(-10)))*(u-((509^(1/2)+23)/10)) = 0
( u-((509^(1/2)+23)/10) )
u-((509^(1/2)+23)/10) = 0 // + (509^(1/2)+23)/10
u = (509^(1/2)+23)/10
( u-((509^(1/2)-23)/(-10)) )
u-((509^(1/2)-23)/(-10)) = 0 // + (509^(1/2)-23)/(-10)
u = (509^(1/2)-23)/(-10)
u in { (509^(1/2)+23)/10, (509^(1/2)-23)/(-10) }
| 2.8=7.3-0.5x | | 3a-8=1 | | -x+7=9x+4 | | -4(r+7)=-46 | | 182=x+2x+(26+x) | | 2(2x-1)+10=9(1+x)-5x | | 2/X-4=7/X+3 | | 15k+4(-2-4k)=-7.8 | | -2(x+2)= | | 3x-3=-3(1-x) | | 15-2x=-9 | | -6n-29=-2nd+4(1-3n) | | b-4+4b=29 | | 9*8*4/1.5=x | | 7+2x=2x-1 | | 9*4*8/1.5 | | -6n-20=-2nd+3(1-3n) | | -7(2p+4)-32=4(5p+2) | | -84+9y+6=3(5y-5)-9 | | 6(-2x+5)=-54 | | 7(z-3)8z-2= | | 275-4x= | | -8n*-8n=-10 | | -7(-3y+2)=-4(3y-2) | | 68=4*7*2+2*2*h | | 3t/s=27 | | 2(5x-2)=10x-4 | | 68=4*7*2+2wh | | -2n(1+5n)= | | a^2-5b^2+1+4b^2+a^2-5= | | 2n(1+5n)= | | -8+-4=4m-2(6m+2) |