2+11=10(a-5)

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Solution for 2+11=10(a-5) equation: 



2+11=10(a-5)

We move all terms to the left:

2+11-(10(a-5))=0

We add all the numbers together, and all the variables

-(10(a-5))+13=0



We calculate terms in parentheses: -(10(a-5)), so:

10(a-5)

We multiply parentheses

10a-50

Back to the equation:

-(10a-50)



We get rid of parentheses

-10a+50+13=0

We add all the numbers together, and all the variables

-10a+63=0

We move all terms containing a to the left, all other terms to the right

-10a=-63

a=-63/-10

a=6+3/10

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