2+16=36x2+16=36

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Solution for 2+16=36x2+16=36 equation:



2+16=36x^2+16=36
We move all terms to the left:
2+16-(36x^2+16)=0
We add all the numbers together, and all the variables
-(36x^2+16)+18=0
We get rid of parentheses
-36x^2-16+18=0
We add all the numbers together, and all the variables
-36x^2+2=0
a = -36; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-36)·2
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*-36}=\frac{0-12\sqrt{2}}{-72} =-\frac{12\sqrt{2}}{-72} =-\frac{\sqrt{2}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*-36}=\frac{0+12\sqrt{2}}{-72} =\frac{12\sqrt{2}}{-72} =\frac{\sqrt{2}}{-6} $

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