2+2(3n-4)=4(n+3)-4

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Solution for 2+2(3n-4)=4(n+3)-4 equation: 



2+2(3n-4)=4(n+3)-4

We move all terms to the left:

2+2(3n-4)-(4(n+3)-4)=0

We multiply parentheses

6n-(4(n+3)-4)-8+2=0



We calculate terms in parentheses: -(4(n+3)-4), so:

4(n+3)-4

We multiply parentheses

4n+12-4

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)



We add all the numbers together, and all the variables

6n-(4n+8)-6=0

We get rid of parentheses

6n-4n-8-6=0

We add all the numbers together, and all the variables

2n-14=0

We move all terms containing n to the left, all other terms to the right

2n=14

n=14/2

n=7

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