2+2(4u-2)=-3(5u-4)+7u

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Solution for 2+2(4u-2)=-3(5u-4)+7u equation: 



2+2(4u-2)=-3(5u-4)+7u

We move all terms to the left:

2+2(4u-2)-(-3(5u-4)+7u)=0

We multiply parentheses

8u-(-3(5u-4)+7u)-4+2=0



We calculate terms in parentheses: -(-3(5u-4)+7u), so:

-3(5u-4)+7u

We add all the numbers together, and all the variables

7u-3(5u-4)

We multiply parentheses

7u-15u+12

We add all the numbers together, and all the variables

-8u+12

Back to the equation:

-(-8u+12)



We add all the numbers together, and all the variables

8u-(-8u+12)-2=0

We get rid of parentheses

8u+8u-12-2=0

We add all the numbers together, and all the variables

16u-14=0

We move all terms containing u to the left, all other terms to the right

16u=14

u=14/16

u=7/8

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