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2+2(5v-1)=-5(2v-3)+2v
We move all terms to the left:
2+2(5v-1)-(-5(2v-3)+2v)=0
We multiply parentheses
10v-(-5(2v-3)+2v)-2+2=0
We calculate terms in parentheses: -(-5(2v-3)+2v), so:We add all the numbers together, and all the variables
-5(2v-3)+2v
We add all the numbers together, and all the variables
2v-5(2v-3)
We multiply parentheses
2v-10v+15
We add all the numbers together, and all the variables
-8v+15
Back to the equation:
-(-8v+15)
10v-(-8v+15)=0
We get rid of parentheses
10v+8v-15=0
We add all the numbers together, and all the variables
18v-15=0
We move all terms containing v to the left, all other terms to the right
18v=15
v=15/18
v=5/6
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