2+2(5x-4)=7-3(2x+1)

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Solution for 2+2(5x-4)=7-3(2x+1) equation:



2+2(5x-4)=7-3(2x+1)
We move all terms to the left:
2+2(5x-4)-(7-3(2x+1))=0
We multiply parentheses
10x-(7-3(2x+1))-8+2=0
We calculate terms in parentheses: -(7-3(2x+1)), so:
7-3(2x+1)
determiningTheFunctionDomain -3(2x+1)+7
We multiply parentheses
-6x-3+7
We add all the numbers together, and all the variables
-6x+4
Back to the equation:
-(-6x+4)
We add all the numbers together, and all the variables
10x-(-6x+4)-6=0
We get rid of parentheses
10x+6x-4-6=0
We add all the numbers together, and all the variables
16x-10=0
We move all terms containing x to the left, all other terms to the right
16x=10
x=10/16
x=5/8

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