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2+2/5(x+1)=x-2x+13/5
We move all terms to the left:
2+2/5(x+1)-(x-2x+13/5)=0
Domain of the equation: 5(x+1)!=0We add all the numbers together, and all the variables
x∈R
2/5(x+1)-(-1x+13/5)+2=0
We get rid of parentheses
2/5(x+1)+1x+2-13/5=0
We calculate fractions
1x+2=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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