2+2n+1=3(6-2n)+5(n+3)

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Solution for 2+2n+1=3(6-2n)+5(n+3) equation:



2+2n+1=3(6-2n)+5(n+3)
We move all terms to the left:
2+2n+1-(3(6-2n)+5(n+3))=0
We add all the numbers together, and all the variables
2n-(3(-2n+6)+5(n+3))+2+1=0
We add all the numbers together, and all the variables
2n-(3(-2n+6)+5(n+3))+3=0
We calculate terms in parentheses: -(3(-2n+6)+5(n+3)), so:
3(-2n+6)+5(n+3)
We multiply parentheses
-6n+5n+18+15
We add all the numbers together, and all the variables
-1n+33
Back to the equation:
-(-1n+33)
We get rid of parentheses
2n+1n-33+3=0
We add all the numbers together, and all the variables
3n-30=0
We move all terms containing n to the left, all other terms to the right
3n=30
n=30/3
n=10

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