2+2x=3(-x+3)-22

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Solution for 2+2x=3(-x+3)-22 equation: 



2+2x=3(-x+3)-22

We move all terms to the left:

2+2x-(3(-x+3)-22)=0

We add all the numbers together, and all the variables

2x-(3(-1x+3)-22)+2=0



We calculate terms in parentheses: -(3(-1x+3)-22), so:

3(-1x+3)-22

We multiply parentheses

-3x+9-22

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)



We get rid of parentheses

2x+3x+13+2=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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