2+3(2u-2)=-2(4u-4)+4u

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Solution for 2+3(2u-2)=-2(4u-4)+4u equation: 



2+3(2u-2)=-2(4u-4)+4u

We move all terms to the left:

2+3(2u-2)-(-2(4u-4)+4u)=0

We multiply parentheses

6u-(-2(4u-4)+4u)-6+2=0



We calculate terms in parentheses: -(-2(4u-4)+4u), so:

-2(4u-4)+4u

We add all the numbers together, and all the variables

4u-2(4u-4)

We multiply parentheses

4u-8u+8

We add all the numbers together, and all the variables

-4u+8

Back to the equation:

-(-4u+8)



We add all the numbers together, and all the variables

6u-(-4u+8)-4=0

We get rid of parentheses

6u+4u-8-4=0

We add all the numbers together, and all the variables

10u-12=0

We move all terms containing u to the left, all other terms to the right

10u=12

u=12/10

u=1+1/5

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