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2+3(2x-7)=9-2(3x+4)
We move all terms to the left:
2+3(2x-7)-(9-2(3x+4))=0
We multiply parentheses
6x-(9-2(3x+4))-21+2=0
We calculate terms in parentheses: -(9-2(3x+4)), so:We add all the numbers together, and all the variables
9-2(3x+4)
determiningTheFunctionDomain -2(3x+4)+9
We multiply parentheses
-6x-8+9
We add all the numbers together, and all the variables
-6x+1
Back to the equation:
-(-6x+1)
6x-(-6x+1)-19=0
We get rid of parentheses
6x+6x-1-19=0
We add all the numbers together, and all the variables
12x-20=0
We move all terms containing x to the left, all other terms to the right
12x=20
x=20/12
x=1+2/3
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