2+3(2x-7)=9-4(3x-1)

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Solution for 2+3(2x-7)=9-4(3x-1) equation: 



2+3(2x-7)=9-4(3x-1)

We move all terms to the left:

2+3(2x-7)-(9-4(3x-1))=0

We multiply parentheses

6x-(9-4(3x-1))-21+2=0



We calculate terms in parentheses: -(9-4(3x-1)), so:

9-4(3x-1)

determiningTheFunctionDomain
-4(3x-1)+9

We multiply parentheses

-12x+4+9

We add all the numbers together, and all the variables

-12x+13

Back to the equation:

-(-12x+13)



We add all the numbers together, and all the variables

6x-(-12x+13)-19=0

We get rid of parentheses

6x+12x-13-19=0

We add all the numbers together, and all the variables

18x-32=0

We move all terms containing x to the left, all other terms to the right

18x=32

x=32/18

x=1+7/9

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