2+3(5x-4)-(6-2x)=12+4(2+x)

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Solution for 2+3(5x-4)-(6-2x)=12+4(2+x) equation:



2+3(5x-4)-(6-2x)=12+4(2+x)
We move all terms to the left:
2+3(5x-4)-(6-2x)-(12+4(2+x))=0
We add all the numbers together, and all the variables
3(5x-4)-(-2x+6)-(12+4(x+2))+2=0
We multiply parentheses
15x-(-2x+6)-(12+4(x+2))-12+2=0
We get rid of parentheses
15x+2x-(12+4(x+2))-6-12+2=0
We calculate terms in parentheses: -(12+4(x+2)), so:
12+4(x+2)
determiningTheFunctionDomain 4(x+2)+12
We multiply parentheses
4x+8+12
We add all the numbers together, and all the variables
4x+20
Back to the equation:
-(4x+20)
We add all the numbers together, and all the variables
17x-(4x+20)-16=0
We get rid of parentheses
17x-4x-20-16=0
We add all the numbers together, and all the variables
13x-36=0
We move all terms containing x to the left, all other terms to the right
13x=36
x=36/13
x=2+10/13

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