2+3(m+5)=4(m+3)

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Solution for 2+3(m+5)=4(m+3) equation: 



2+3(m+5)=4(m+3)

We move all terms to the left:

2+3(m+5)-(4(m+3))=0

We multiply parentheses

3m-(4(m+3))+15+2=0



We calculate terms in parentheses: -(4(m+3)), so:

4(m+3)

We multiply parentheses

4m+12

Back to the equation:

-(4m+12)



We add all the numbers together, and all the variables

3m-(4m+12)+17=0

We get rid of parentheses

3m-4m-12+17=0

We add all the numbers together, and all the variables

-1m+5=0

We move all terms containing m to the left, all other terms to the right

-m=-5

m=-5/-1

m=+5

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