2+3(x-2)=11-7(x-1)

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Solution for 2+3(x-2)=11-7(x-1) equation: 



2+3(x-2)=11-7(x-1)

We move all terms to the left:

2+3(x-2)-(11-7(x-1))=0

We multiply parentheses

3x-(11-7(x-1))-6+2=0



We calculate terms in parentheses: -(11-7(x-1)), so:

11-7(x-1)

determiningTheFunctionDomain
-7(x-1)+11

We multiply parentheses

-7x+7+11

We add all the numbers together, and all the variables

-7x+18

Back to the equation:

-(-7x+18)



We add all the numbers together, and all the variables

3x-(-7x+18)-4=0

We get rid of parentheses

3x+7x-18-4=0

We add all the numbers together, and all the variables

10x-22=0

We move all terms containing x to the left, all other terms to the right

10x=22

x=22/10

x=2+1/5

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