2+3(z+1)=3z-6z-3

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Solution for 2+3(z+1)=3z-6z-3 equation:



2+3(z+1)=3z-6z-3
We move all terms to the left:
2+3(z+1)-(3z-6z-3)=0
We add all the numbers together, and all the variables
3(z+1)-(-3z-3)+2=0
We multiply parentheses
3z-(-3z-3)+3+2=0
We get rid of parentheses
3z+3z+3+3+2=0
We add all the numbers together, and all the variables
6z+8=0
We move all terms containing z to the left, all other terms to the right
6z=-8
z=-8/6
z=-1+1/3

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