2+3(z+1)=3z-6z-3

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Solution for 2+3(z+1)=3z-6z-3 equation: 



2+3(z+1)=3z-6z-3

We move all terms to the left:

2+3(z+1)-(3z-6z-3)=0

We add all the numbers together, and all the variables

3(z+1)-(-3z-3)+2=0

We multiply parentheses

3z-(-3z-3)+3+2=0

We get rid of parentheses

3z+3z+3+3+2=0

We add all the numbers together, and all the variables

6z+8=0

We move all terms containing z to the left, all other terms to the right

6z=-8

z=-8/6

z=-1+1/3

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