2+3(z-3)=z+3z+6z.

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Solution for 2+3(z-3)=z+3z+6z. equation: 



2+3(z-3)=z+3z+6z.

We move all terms to the left:

2+3(z-3)-(z+3z+6z.)=0

We add all the numbers together, and all the variables

3(z-3)-(+4z+6z.)+2=0

We multiply parentheses

3z-(+4z+6z.)-9+2=0

We get rid of parentheses

3z-4z-6z.-9+2=0

We add all the numbers together, and all the variables

-1z-6z.-7=0

We move all terms containing z to the left, all other terms to the right

-1z-6z.=7

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