2+3/2u-6=-5/u-3

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Solution for 2+3/2u-6=-5/u-3 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(3/2)*u-6+2 = -5/u-3 // + -5/u-3

(3/2)*u-(-5/u)-6+2+3 = 0

(3/2)*u+5*u^-1-6+2+3 = 0

3/2*u^1+5*u^-1-1*u^0 = 0

(3/2*u^2-1*u^1+5*u^0)/(u^1) = 0 // * u^2

u^1*(3/2*u^2-1*u^1+5*u^0) = 0

u^1

(3/2)*u^2-u+5 = 0

(3/2)*u^2-u+5 = 0

DELTA = (-1)^2-(4*5*(3/2))

DELTA = -29

DELTA < 0

u in { } 

u belongs to the empty set

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