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2+3/5x=-4+2/3x
We move all terms to the left:
2+3/5x-(-4+2/3x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/5x-(2/3x-4)+2=0
We get rid of parentheses
3/5x-2/3x+4+2=0
We calculate fractions
9x/15x^2+(-10x)/15x^2+4+2=0
We add all the numbers together, and all the variables
9x/15x^2+(-10x)/15x^2+6=0
We multiply all the terms by the denominator
9x+(-10x)+6*15x^2=0
Wy multiply elements
90x^2+9x+(-10x)=0
We get rid of parentheses
90x^2+9x-10x=0
We add all the numbers together, and all the variables
90x^2-1x=0
a = 90; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·90·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*90}=\frac{0}{180} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*90}=\frac{2}{180} =1/90 $
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