2+3c=-2(-2c)+2(6)

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Solution for 2+3c=-2(-2c)+2(6) equation: 



2+3c=-2(-2c)+2(6)

We move all terms to the left:

2+3c-(-2(-2c)+2(6))=0



We calculate terms in parentheses: -(-2(-2c)+26), so:

-2(-2c)+26

We multiply parentheses

4c+26

Back to the equation:

-(4c+26)



We get rid of parentheses

3c-4c-26+2=0

We add all the numbers together, and all the variables

-1c-24=0

We move all terms containing c to the left, all other terms to the right

-c=24

c=24/-1

c=-24

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