2+3n=2(n+1)+n

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Solution for 2+3n=2(n+1)+n equation: 



2+3n=2(n+1)+n

We move all terms to the left:

2+3n-(2(n+1)+n)=0



We calculate terms in parentheses: -(2(n+1)+n), so:

2(n+1)+n

We add all the numbers together, and all the variables

n+2(n+1)

We multiply parentheses

n+2n+2

We add all the numbers together, and all the variables

3n+2

Back to the equation:

-(3n+2)



We get rid of parentheses

3n-3n-2+2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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