2+3r=-(3r+6)+5r

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Solution for 2+3r=-(3r+6)+5r equation: 



2+3r=-(3r+6)+5r

We move all terms to the left:

2+3r-(-(3r+6)+5r)=0



We calculate terms in parentheses: -(-(3r+6)+5r), so:

-(3r+6)+5r

We add all the numbers together, and all the variables

5r-(3r+6)

We get rid of parentheses

5r-3r-6

We add all the numbers together, and all the variables

2r-6

Back to the equation:

-(2r-6)



We get rid of parentheses

3r-2r+6+2=0

We add all the numbers together, and all the variables

r+8=0

We move all terms containing r to the left, all other terms to the right

r=-8

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