2+3x(3x-1)+7=8-(3-2x)

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Solution for 2+3x(3x-1)+7=8-(3-2x) equation: 



2+3x(3x-1)+7=8-(3-2x)

We move all terms to the left:

2+3x(3x-1)+7-(8-(3-2x))=0

We add all the numbers together, and all the variables

3x(3x-1)-(8-(-2x+3))+2+7=0

We add all the numbers together, and all the variables

3x(3x-1)-(8-(-2x+3))+9=0

We multiply parentheses

9x^2-3x-(8-(-2x+3))+9=0



We calculate terms in parentheses: -(8-(-2x+3)), so:

8-(-2x+3)

determiningTheFunctionDomain
-(-2x+3)+8

We get rid of parentheses

2x-3+8

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

9x^2-3x-2x-5+9=0

We add all the numbers together, and all the variables

9x^2-5x+4=0

a = 9; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·9·4
Δ = -119
Delta is less than zero, so there is no solution for the equation

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