2+3x+8x=3(x+2)+7(2x-4)

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Solution for 2+3x+8x=3(x+2)+7(2x-4) equation: 



2+3x+8x=3(x+2)+7(2x-4)

We move all terms to the left:

2+3x+8x-(3(x+2)+7(2x-4))=0

We add all the numbers together, and all the variables

11x-(3(x+2)+7(2x-4))+2=0



We calculate terms in parentheses: -(3(x+2)+7(2x-4)), so:

3(x+2)+7(2x-4)

We multiply parentheses

3x+14x+6-28

We add all the numbers together, and all the variables

17x-22

Back to the equation:

-(17x-22)



We get rid of parentheses

11x-17x+22+2=0

We add all the numbers together, and all the variables

-6x+24=0

We move all terms containing x to the left, all other terms to the right

-6x=-24

x=-24/-6

x=+4

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