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2+3x=-4(5+x2)
We move all terms to the left:
2+3x-(-4(5+x2))=0
We add all the numbers together, and all the variables
-(-4(+x^2+5))+3x+2=0
We calculate terms in parentheses: -(-4(+x^2+5)), so:We get rid of parentheses
-4(+x^2+5)
We multiply parentheses
-4x^2-20
Back to the equation:
-(-4x^2-20)
4x^2+3x+20+2=0
We add all the numbers together, and all the variables
4x^2+3x+22=0
a = 4; b = 3; c = +22;
Δ = b2-4ac
Δ = 32-4·4·22
Δ = -343
Delta is less than zero, so there is no solution for the equation
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