2+3x=2(-x+9)-36

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Solution for 2+3x=2(-x+9)-36 equation: 



2+3x=2(-x+9)-36

We move all terms to the left:

2+3x-(2(-x+9)-36)=0

We add all the numbers together, and all the variables

3x-(2(-1x+9)-36)+2=0



We calculate terms in parentheses: -(2(-1x+9)-36), so:

2(-1x+9)-36

We multiply parentheses

-2x+18-36

We add all the numbers together, and all the variables

-2x-18

Back to the equation:

-(-2x-18)



We get rid of parentheses

3x+2x+18+2=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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