2+3z+6=z-3z-7

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Solution for 2+3z+6=z-3z-7 equation: 



2+3z+6=z-3z-7

We move all terms to the left:

2+3z+6-(z-3z-7)=0

We add all the numbers together, and all the variables

3z-(-2z-7)+2+6=0

We add all the numbers together, and all the variables

3z-(-2z-7)+8=0

We get rid of parentheses

3z+2z+7+8=0

We add all the numbers together, and all the variables

5z+15=0

We move all terms containing z to the left, all other terms to the right

5z=-15

z=-15/5

z=-3

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