2+3z-2=4z-3(z+1)32

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Solution for 2+3z-2=4z-3(z+1)32 equation: 



2+3z-2=4z-3(z+1)32

We move all terms to the left:

2+3z-2-(4z-3(z+1)32)=0

We add all the numbers together, and all the variables

3z-(4z-3(z+1)32)=0



We calculate terms in parentheses: -(4z-3(z+1)32), so:

4z-3(z+1)32

We multiply parentheses

4z-96z-96

We add all the numbers together, and all the variables

-92z-96

Back to the equation:

-(-92z-96)



We get rid of parentheses

3z+92z+96=0

We add all the numbers together, and all the variables

95z+96=0

We move all terms containing z to the left, all other terms to the right

95z=-96

z=-96/95

z=-1+1/95

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