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2+4(3x+2)=2(5x+1)+14
We move all terms to the left:
2+4(3x+2)-(2(5x+1)+14)=0
We multiply parentheses
12x-(2(5x+1)+14)+8+2=0
We calculate terms in parentheses: -(2(5x+1)+14), so:We add all the numbers together, and all the variables
2(5x+1)+14
We multiply parentheses
10x+2+14
We add all the numbers together, and all the variables
10x+16
Back to the equation:
-(10x+16)
12x-(10x+16)+10=0
We get rid of parentheses
12x-10x-16+10=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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