2+4(4x-7)=34+6x

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Solution for 2+4(4x-7)=34+6x equation: 



2+4(4x-7)=34+6x

We move all terms to the left:

2+4(4x-7)-(34+6x)=0

We add all the numbers together, and all the variables

4(4x-7)-(6x+34)+2=0

We multiply parentheses

16x-(6x+34)-28+2=0

We get rid of parentheses

16x-6x-34-28+2=0

We add all the numbers together, and all the variables

10x-60=0

We move all terms containing x to the left, all other terms to the right

10x=60

x=60/10

x=6

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