2+4(d-2)=3-(d-1)

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Solution for 2+4(d-2)=3-(d-1) equation: 



2+4(d-2)=3-(d-1)

We move all terms to the left:

2+4(d-2)-(3-(d-1))=0

We multiply parentheses

4d-(3-(d-1))-8+2=0



We calculate terms in parentheses: -(3-(d-1)), so:

3-(d-1)

determiningTheFunctionDomain
-(d-1)+3

We get rid of parentheses

-d+1+3

We add all the numbers together, and all the variables

-1d+4

Back to the equation:

-(-1d+4)



We add all the numbers together, and all the variables

4d-(-1d+4)-6=0

We get rid of parentheses

4d+1d-4-6=0

We add all the numbers together, and all the variables

5d-10=0

We move all terms containing d to the left, all other terms to the right

5d=10

d=10/5

d=2

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