2+4(m+3)=6(5-m)

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Solution for 2+4(m+3)=6(5-m) equation: 



2+4(m+3)=6(5-m)

We move all terms to the left:

2+4(m+3)-(6(5-m))=0

We add all the numbers together, and all the variables

4(m+3)-(6(-1m+5))+2=0

We multiply parentheses

4m-(6(-1m+5))+12+2=0



We calculate terms in parentheses: -(6(-1m+5)), so:

6(-1m+5)

We multiply parentheses

-6m+30

Back to the equation:

-(-6m+30)



We add all the numbers together, and all the variables

4m-(-6m+30)+14=0

We get rid of parentheses

4m+6m-30+14=0

We add all the numbers together, and all the variables

10m-16=0

We move all terms containing m to the left, all other terms to the right

10m=16

m=16/10

m=1+3/5

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