2+4+x=8+2(3+x)-3

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Solution for 2+4+x=8+2(3+x)-3 equation: 



2+4+x=8+2(3+x)-3

We move all terms to the left:

2+4+x-(8+2(3+x)-3)=0

We add all the numbers together, and all the variables

x-(8+2(x+3)-3)+2+4=0

We add all the numbers together, and all the variables

x-(8+2(x+3)-3)+6=0



We calculate terms in parentheses: -(8+2(x+3)-3), so:

8+2(x+3)-3

determiningTheFunctionDomain
2(x+3)+8-3

We add all the numbers together, and all the variables

2(x+3)+5

We multiply parentheses

2x+6+5

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

x-2x-11+6=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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