2+4/y=7/12y

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Solution for 2+4/y=7/12y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4/y+2 = (7/12)*y // - (7/12)*y

4/y-((7/12)*y)+2 = 0

(-7/12)*y+4/y+2 = 0

4*y^-1-7/12*y^1+2*y^0 = 0

(2*y^1-7/12*y^2+4*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^1-7/12*y^2+4*y^0) = 0

y^1

(-7/12)*y^2+2*y+4 = 0

(-7/12)*y^2+2*y+4 = 0

DELTA = 2^2-(4*4*(-7/12))

DELTA = 40/3

DELTA > 0

y = ((40/3)^(1/2)-2)/(2*(-7/12)) or y = (-(40/3)^(1/2)-2)/(2*(-7/12))

y = -6/7*((40/3)^(1/2)-2) or y = 6/7*((40/3)^(1/2)+2)

y in { -6/7*((40/3)^(1/2)-2), 6/7*((40/3)^(1/2)+2)} 

y in { -6/7*((40/3)^(1/2)-2), 6/7*((40/3)^(1/2)+2) }

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